Vinoba Bhave University (VBU), Hazaribag invites online application for the admission into M.Sc. (Mathematics and Computing) Courses 2019.
Vinoba Bhave University Admissions 2019:
1. M.Sc. (Mathematics): 60 Seats
Duration of Course: 2 years (4 semesters)
Eligibility: B.A./B.Sc. (Mathematics) Hons., B.A./B.Sc. with one Paper Mathematics in each semester or B.C.A. with Mathematics in each year (Two semesters) from any recognized Indian University, B.Sc (Maths) Hons. appearing candidates.
Selection Procedure: On the basis of Entrance Exam and Counseling.
Course Fee: Rs. 25000/- per semester
Entrance Exam Fee: Rs. 1000/-
Application Process: Application form, syllabus for entrance exam can be obtained from the department of Mathematics or from the website www.vbu.ac.in and duly filled form can be submitted to The Head, University Department of Mathematics, Vinoba Bhave University, Hazaribag-825319, Jharkhand (by hand or by post).
Important Dates:
Last Date: 27th July 2019
Date of Entrance Exam: 30ty July 2019
Dates of Counselling: 05th to 6th August 2019
Date of Commencement of Classes: 10th August 2019
Contact Details:
Vinoba Bhave University (VBU),
NH 33, Sindoor, Hazaribagh, Jharkhand-825301
Phone: 06546-261922, 943132889,
website www.vbu.ac.in
For Vinoba Bhave University Admissions 2019 M.Sc. (Maths & Computing) Course: Visit Here www.vbu.ac.in